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Q.15

A
amit110025
asked on 11 month ago

Q.15

neon approach for this?😀

C
coquerordarkhorse
asked on 6 month ago

/A is right........................... Let the speed of Seeta=S and Speed of geeta= G so by formula S/G=Sqrt(9/8) i.eS/G=3/2(sqrt2) now From here S comes out to be 3 KM/hr

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