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Factor theorm

A
amitkumar1295
asked on 8 month ago

Factor theorm

Q No 21 22 23 by formula kaise bnayenge

C
coquerordarkhorse
asked on 6 month ago

Q.NO 21--Factors of 20=2^2*5 SUM of even factors=(2^1+2^2)*(5^0+5^1)=36 Q.NO 22--Factors of 30=2*3*5 SUM of even factors= (2^1)(3^0+3^1)(5^0+5^1)=48 Q.NO 23--Factors of 100=2^2*5^2 SUM of even factors=(2^1+2^2)(5^0+5^1+5^2)=186

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